Pls solve 2nd question

Pls solve 2nd question MATHEMAncs

f (x) = \frac{e^{x} - e^{- x}}{2} f (g (x)) = x W e k n o w f (f^{- 1} (x)) = x C o m p a r i n g w e h a v e g (x) = f^{- 1} (x) g (\frac{e^{1002} - 1}{2 e^{501}}) = f^{- 1} (\frac{e^{1002} - 1}{2 e^{501}}) g (\frac{\frac{e^{1002}}{e^{501}} - \frac{1}{e^{501}}}{2}) = f^{- 1} (\frac{\frac{e^{1002}}{e^{501}} - \frac{1}{e^{501}}}{2}) g (\frac{e^{501} - e^{- 501}}{2}) = f^{- 1} (\frac{e^{501} - e^{- 501}}{2}) N o t e : \frac{e^{501} - e^{- 501}}{2} = f (501) g (\frac{e^{501} - e^{- 501}}{2}) = f^{- 1} (f (501)) S i n c e f^{- 1} (f (x)) = x g (\frac{e^{501} - e^{- 501}}{2}) = 501