Pls solve 4 and 5

 Q4. (a) What should be added to x2 + xy + y2 to obtain 2x2 + 3xy?

​        (b) What should be subtracted from 2a + 8b + 10 to get – 3a + 7b + 16 ?


Q5. What should be taken away from 3x2 – 4y2 + 5 xy + 20 to obtain – x2  – y2  + 6xy + 20 ? 
 

Dear Student,

Q.4 a Let the quantity to be added to x2+xy+y2 be AThen, x2+xy+y2+A =2x2+3xyA =2x2+3xy- x2+xy+y2A = 2x2+3xy-x2-xy-y2A = x2+2xy-y2Hence, x2+2xy-y2 must be added to x2+xy+y2 to obtain 2x2+3xyQ.5 Let the quantity to be subtracted from 3x2-4y2+5xy+20 be A.Then, 3x2-4y2+5xy+20-A=-x2-y2+6xy+20A = 3x2-4y2+5xy+20+x2+y2-6xy-20A= 4x2-3y2-xyHence, 4x2-3y2-xy must be subtracted from 3x2-4y2+5xy+20 to get -x2-y2+6xy+20.

Regards

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