pls solve asap
Dear student,
let us consider matrix P=A and matrix Q=B
given
A and B are equal matrices of the same order such that AB = BA.
For n = 1, we have:
Therefore, the result is true for n = 1.
Let the result be true for n = k.
Now, we prove that the result is true for n = k + 1.
Therefore, the result is true for n = k + 1.
Thus, by the principle of mathematical induction, we have
hence PQn=QnP for all n belongs to N
Now, we prove that for all n ∈ N
For n = 1, we have:
Therefore, the result is true for n = 1.
Let the result be true for n = k.
Now, we prove that the result is true for n = k + 1.
Therefore, the result is true for n = k + 1.
Thus, by the principle of mathematical induction, we have, for all natural numbers.
hence(PQ)n=QnPn
regards,