Pls solve dis que.!

Dear student,

Let dimension of x,  $\left[x\right]=\mathrm{L}$
So, by dimensional analysis,
$$\begin{gathered} \left[ax\right]=\left[x^2\right]={\mathrm{L}}^2 \\ \Rightarrow \left[a\right]=\mathrm{L} \end{gathered}$$
Integration sign do not affect dimensions.
So, dimension of LHS,
$\frac{\left[x\right]}{\sqrt{\left[x^2\right]}}=\frac{\mathrm{L}}{\mathrm{L}}=\mathrm{Dimensionless}$
Thus, RHS is also dimensionless,
So, value of n = 0.

Regards