pls solve limit x--->0 [root(1 + sinx) - root(1- sinx)] / tanx Share with your friends Share 1 Varun Rawat answered this limx→01 + sin x - 1 - sin xtan x=limx→0 1 + sin x - 1 - sin xtan x ×1 + sin x + 1 - sin x1 + sin x + 1 - sin x=limx→01 + sin x - 1 + sin xtan x1 + sin x + 1 - sin x=limx→02 sin x × cos xsin x 1 + sin x + 1 - sin x=limx→0 2 cos x1 + sin x + 1 - sin x=2 cos 01 + sin 0 + 1 - sin 0=21 + 1=22=1 1 View Full Answer
