Pls solve!!!!! Pls!!! Share with your friends Share 0 Vaibhav Tiwari answered this Dear Student, B=2B0sinθB=2×μ04πmr2×7r2μ04πmr2×7r=0.4×10-42×10-7×7m72+18232×104=0.4×10-4m=4×10-2×3733214M=m×14 cm=m×14100M=4×10-2×3733214×14100=2.88 J/T Regards 0 View Full Answer