pls solve problem no. 19

pls solve problem no. 19 • f the A em 'ong. 60 wide. em high. A metal block '-m by 'S is into the tank and Find in the amount the level rises, Find the Of wood required for making thc bov with internal dimensions : 20cm by cm by cm wood I .25 cm thick. 18. Find the of wood required for making the .yv•nbavwith external dimensions 17.5 cm long, 14 wide, 10 cm high, wood 7.5 mm thick. 19. A field is 30 m long and 18 m broad. A pit 6 m long. 4 m wide and 3 m deep, is dug out from the middle of the field and the earth removed is evenly spread over the remaining area to the field. Find the rise in the level of the remaining part of the field in centimetres correct to one decimal place. (ICSE) 20. An agricultural field is in the form ofa rectangle of length 20 m and width 14 m. A pit 6 m long 3 m wide and 2.5 m deep is dug in the corner of the field and the earth taken out from the pit is spread uniformaly over the remaining area of the field. Find the extent to which the level of the field has been raised. A certain quality of wood costs 2 3

Dear Student,

Given, Field length L_{1} = 30 m width B_{1} = 18 m let height H_{1} = x Area of field = 30 \times 18 = 540 m^{2} Given Measurement of pit, length L_{2} = 6 m width B_{2} = 4 m height H_{2} = 3 m Volume of earth dug out from pit = 6 \times 4 \times 3 = 72 m^{3} Area of pit = 6 \times 4 = 24 m^{2} Remaining Area of field = (540 - 24) = 516 m^{2} pit is evenly spread over field so, volume of remaining field = volume of pit L_{1} \times B_{1} \times H_{1} = L_{2} \times B_{2} \times H_{2} Rise in level (x) = \frac{72}{516} x = 0.139 m x = 13.9 cm Hence the rise in level of field is 13.9 cm

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