Pls solve Q1.
Dear student.
Here given volume is 11200cm3 which is equal to 11.2L.
1 mole of a gas occupies 22.4 L at STP,
so Molar Mass that is, mass of 1 mole of chlorine gas equals to 35.5 g.
According to the fact, volume of gas at STP = Number of moles * 11.2
22.4L = n * 11.2
n = 2
Thus n= 2.
This means that atomicity of chlorine is 2.
Regards
Here given volume is 11200cm3 which is equal to 11.2L.
1 mole of a gas occupies 22.4 L at STP,
so Molar Mass that is, mass of 1 mole of chlorine gas equals to 35.5 g.
According to the fact, volume of gas at STP = Number of moles * 11.2
22.4L = n * 11.2
n = 2
Thus n= 2.
This means that atomicity of chlorine is 2.
Regards