Dear Student When i=0,μ1sin i=μ2sinri=0⇒sin r=0⇒r=0 So it will be straight line as shown in figureWhen i=45,μ1sin i=μ2sinr1 sin 45=43sin r⇒r=32 02 which is less than 45 that means it will move towards normal as shown in diagram Regards

Pls solve Q25.

Dear Student

W h e n i = 0, μ_{1} \sin i = μ_{2} \sin r i = 0 \Rightarrow \sin r = 0 \Rightarrow r = 0 S o i t w i l l b e s t r a i g h t l i n e a s s h o w n i n f i g u r e W h e n i = 45, μ_{1} \sin i = μ_{2} \sin r 1 \sin 45 = \frac{4}{3} \sin r \Rightarrow r = 32.02 w h i c h i s l e s s t h a n 45 t h a t m e a n s i t w i l l m o v e t o w a r d s n o r m a l a s s h o w n i n d i a g r a m

Regards

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