Pls solve Q31
Dear student,
GIVEN : weight of mix of NaOH and Na2CO3 =2.013 gm
Total volume of solution =250 ml
Amount of solution taken = 10ml
acid required for neutralization = 20 ml 0.1 N H2SO4
In the mixture both NaOH and Na2CO3 were neutralized by H2SO4
Let the amount of Na2CO3 =x gm
so amount of NaOH =2.013-x gm
Equivalents of sodium carbonate =
equivalents of sodium hydroxide =
milliequivalents of sodium carbonate =
so in 10 ml of mixture mlli-equivalents =
similarly milliequivalents of sodium hydroxide in 25 ml =
(NV)mix=(NV)H2SO4
x= 5.31 gm
% Na2CO3 =
Regards!
GIVEN : weight of mix of NaOH and Na2CO3 =2.013 gm
Total volume of solution =250 ml
Amount of solution taken = 10ml
acid required for neutralization = 20 ml 0.1 N H2SO4
In the mixture both NaOH and Na2CO3 were neutralized by H2SO4
Let the amount of Na2CO3 =x gm
so amount of NaOH =2.013-x gm
Equivalents of sodium carbonate =
equivalents of sodium hydroxide =
milliequivalents of sodium carbonate =
so in 10 ml of mixture mlli-equivalents =
similarly milliequivalents of sodium hydroxide in 25 ml =
(NV)mix=(NV)H2SO4
x= 5.31 gm
% Na2CO3 =
Regards!