Dear Student, Here before pressing key equivalent capicitonce =20×3020+50=12μFso charges on them =CV=12×24=288μCBut after pressing keycharge on C1=20×12=240μCand on C2=30×12=360μCSo charge through path 1=288-240=48μCcharge through path2 =360-288=72μCand through path3=72-48=24μC Regards

Pls solve Q33

Dear Student,

H e r e b e f o r e p r e s \sin g k e y e q u i v a l e n t c a p i c i t o n c e = \frac{20 \times 30}{20 + 50} = 12 μ F s o c h a r g e s o n t h e m = C V = 12 \times 24 = 288 μ C B u t a f t e r p r e s \sin g k e y c h a r g e o n C_{1} = 20 \times 12 = 240 μ C a n d o n C_{2} = 30 \times 12 = 360 μ C S o c h a r g e t h r o u g h p a t h 1 = 288 - 240 = 48 μ C c h a r g e t h r o u g h p a t h 2 = 360 - 288 = 72 μ C a n d t h r o u g h p a t h 3 = 72 - 48 = 24 μ C

Regards

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