Pls solve ques-8 in this photo Q8. In the given figure show that ∆ ABC ≅ ∆ DCB Share with your friends Share 0 Lovina Kansal answered this Dear student In △BOC,by angle sum property of △∠OBC+∠OCB+∠BOC=180°⇒25°+25°+∠BOC=180°⇒∠BOC=130°Also,∠BOC+∠AOB=180° [Linear pair]⇒∠AOB=180°-130°=50°Also,∠AOB=∠COD=50° [Vertically opposite angle]Also,In △AOB, by angle sum property of △∠ABO+∠AOB+∠BAO=180°⇒105°+50°+∠BAO=180°⇒∠BAO=25°Similarly by angle sum property of △ in △COD∠DCO=125°Now, In △ABC and △DCB∠BAC=∠CDB=25°∠ABC=∠DCB=25°+105°=130°and ∠ACB=∠DBC=25°So, △ABC≅△DCB [By AA-criterion] Regards 1 View Full Answer Adithya Rajesh answered this x=80;so 180-80=100 the ans -1 Sharanya💜 answered this I am asking the ans of ques 8 not 9 1