Pls solve ques-8 in this photo


Q8. In the given figure show that   ABC   ​ DCB
         
 

Dear student


In BOC,by angle sum property of OBC+OCB+BOC=180°25°+25°+BOC=180°BOC=130°Also,BOC+AOB=180°    [Linear pair]AOB=180°-130°=50°Also,AOB=COD=50°     [Vertically opposite angle]Also,In AOB, by angle sum property of ABO+AOB+BAO=180°105°+50°+BAO=180°BAO=25°Similarly by angle sum property of  in CODDCO=125°Now,  In ABC and DCBBAC=CDB=25°ABC=DCB=25°+105°=130°and ACB=DBC=25°So, ABCDCB    [By AA-criterion]
Regards

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x=80;so 180-80=100 the ans
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I am asking the ans of ques 8 not 9
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