Pls solve the below question.

Dear student,
Let the denominator be 'x'then numerator=x-4Acc. to question,x-4+1x+1=12 x-3x+1=12 2x-3=x+12x-6=x+12x-x=1+6x=7Thus, the denominator=7and numerator=7-4=3Hence required fraction is 37.
Regards

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