Pls solve the question 12 fast

D e a r s t u d e n t, L e t t h e e d g e s o f c u b e s f o r m e d a f t e r m e l t i n g b e a N o w t h e v o l u m e o f t h e o r i g i n a l c u b e = v o l u m e o f 27 c u b e s f o r m e d a f t e r m e l t i n g 6 \times 6 \times 6 = 27 \times a \times a \times a a \times a \times a = \frac{6 \times 6 \times 6}{27} a \times a \times a = \frac{6 \times 6 \times 6}{3 \times 3 \times 3} = 2 \times 2 \times 2 a = 2 c m R e g a r d s

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