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D e a r s t u d e n t, G i v e n, A B C D i s a r e c \tan g l e w i t h A B = 14 c m a n d B C = 7 c m T h e a r e a o f s h a d e d r e g i o n = A r e a o f r e c \tan g l e A B C D + 2 x a r e a o f s e m i c i r c l e w i t h A D a n d B C a s d i a m e t e r s - a r e a o f t h e s e m i c i r c l e w i t h D C a s d i a m e t e r = 14 \times 7 + 2 \times \frac{1}{2} \times π \times {(\frac{7}{2})}^{2} - \frac{1}{2} \times π \times 7^{2} = 59.5 {cm}^{2} Perimeter of shaded region = AD + 2 \times perimeter of semicircle + perimeter of big circle = 14 + 2 \times π \times (\frac{7}{2}) + 2 \times π \times 7 = 14 + 22 + 44 = 80 cm Regards R e g a r d s

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