Pls solve this
Illustration 6.93 Find the number of ways in which six persons can be seated at a round table, so that all shall not have the same neighbors in any two arrangements.
 

Dear student
The number of ways seating 6 persons=5!But in clockwise and counter-clockwise arrangements same persons areneighbours and therefore, these two arrangements are the same.Hence the required number=12×5!=12×5×4×3×2=60
Regards

  • 0
What are you looking for?