Pls solve this sum number 2 and also explain how to identify how to solve

Dear Student, In XeF₂,total number of valence electrons of Xe=8, two electrons are shared with 2F atoms,6 electrons are left hence 3 lone pairs. In XeF₄,total number of valence electrons of Xe=8,4 electrons are shared with 4F atoms ,4 electrons are left hence 2 lone pairs. In XeF₆,total number of valence electrons of Xe=8,6 electrons are shared with 6F atoms ,2 electrons are left hence 1 lone pair. Correct answer is D. Regards

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