Pls solve this

Wrong ans.
It is true pls. Give me explanation

Hope this will help you a bit!!

We know that e raise to the power logx is always = x. So it will be defined for all real x.

Brother my answer is correct log is not defined if x is less than or equal to zero.your answer book may have misprint.

Preetam singh - aap ncert ka 5th chap. Ka example dekh lo

Preetam its an NCERT Book's example it is not a misprint

To Prove that:-
e^(log x) = x
Taking log on both sides,
log x*log e = log x
(As log e =1)
Implies,log x = log x
LHS = RHS
Hence,proved.
Let's try to solve this for negative values of x,
e^log(-x) = (-x)
Taking log on both sides,
log(-x)=log(-x)
Taking antilog on both sides,
-x = -x
LHS=RHS 
Hence,proved
Lets prove this for x=0,
e^(log0)=0
Taking log on both the sides,
log 0 = log 0
Antilog, 0=0
LHS = RHS 
Hence,proved.
The range of e^(logx) or (log x) doesn't matter because we are just expressing a^x = e^x ln a,whenever we take antilog on both the sides,the expression is satisfied.Hence x may be >=< 0.