pls solve with steps A circle of radius r touches the line 2x + 3y + 1 = 0 - Maths - Three Dimensional Geometry

Question

pls solve with steps

A circle of radius r touches the line 2x +
3y + 1 = 0 at the point (1, −1) and is orthogonal to
the circle with (0, −1) and (−2, 3) as end points of
the diameter Then the value of 208 r 2 9 - 4 is

Shilpa Patel · Accepted Answer

pls solve with steps A circle of radius r touches the line 2x + 3y + 1 = 0 at the point (1, −1) and is orthogonal to the circle with (0, −1) and (−2, 3) as end points of the diameter. Then the value of 208 r 2 9 - 4 is

pls solve with steps

A circle of radius r touches the line 2x + 3y + 1 = 0 at the point (1, −1) and is orthogonal to the circle with (0, −1) and (−2, 3) as end points of the diameter. Then the value of $(\sqrt{\frac{208 r^{2}}{9}} - 4)$ is