Pls solve

Dear Student,

Please find below the solution to the asked query:

We can simplify the circuit by finding the effective emf​ and effective internal resistance of the circuit.


The situation of simplification is as shown in the figure below.

1reff=1r1+1r2+1r31reff=11+12+111reff=2+121reff=52reff=25 Ω

and the effective emf is,

εemfreff=ε1r1+ε2r2+ε3r3εemfreff=31-42+61εemf25=3-2+6εeff=25×7εeff=145 ΩSo,I=1451.6+0.4=1410=1.4 ASo,VR=IR=1.4×1.6=2.24 VSo,2.24=3-I1I1=0.76 A2.24=-4-2I2I2=-6.242 A=-3.12 A2.24=6-I3I3=3.76 A

So, the current in the 2 ohm resistor flows in the opposite direction to the direction shown in the figure.​

 

Hope this information will clear your doubts about the topic.

If you have any more doubts just ask here on the forum and our experts will try to help you out as soon as possible.

Regards

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