Plss solve this.. Share with your friends Share 0 Kavita Verma answered this Dear Student, Total number of consumers = 4+5+13+20+14+8+4 = 68half of 68 = 34cumulative frequency of 65 - 85 class = 4cumulative frequency of 85 - 105 class = 4 + 5 = 9cumulative frequency of 105 - 125 class =9 + 13 = 22cumulative frequency of 125 - 145 class = 22 + 20 = 42So median class = 125 - 145 As we take that class which has cumulative frequency just > 34(a) lower limit of median class = 125So, option (i) is correct(b) modal class is the class which have highest number of consumersSo, 125 - 145 is the modal classlower limit of modal class is (i) 125(c) upper limit of median class = 145upper limit of modal class = 145mean of upper limit of median and modal class = 145 + 1452 = 145So, correct option is (ii) 145(d) width of class = upper limit - lower limit = 85 - 65 = 20So correct option is (ii) 20(e) median = L + n2 - f1f × hwhere L = lower limit of median class = 125n = total number of consumers == 68. So, n2 = 34f1 = cumulative frequency of class before median class = 22f = frequency of the median class = 20h = class width = 20median = 125 + 34 - 2220 × 20 = 125 + 12 = 137So, correct option is i 137 Regards, 1 View Full Answer Shweta Jha answered this Hiiiii 0 Shayaan answered this Hi 0
