Plsss solvve this quess

Dear Student,

= \sum_{k = 1}^{10} (3 + 2^{k + 1}) = \sum_{k = 1}^{10} 3 + \sum_{k = 1}^{10} 2^{k + 1} = 3 \times 10 + (2^{2} + 2^{3} + 2^{4} + 2^{5} + 2^{6} + . . . + 2^{11}) = 30 + A - - - - - (1) A = 2^{2} (1 + 2 + 2^{2} + . . . + 2^{9}) A i s a G . P . w i t h f i r s t t e r m = a a n d c o m m o n r a t i o = 2 S_{n} = a \frac{(r^{n} - 1)}{(r - 1)} S = 1 (\frac{2^{9} - 1}{2 - 1}) S = 2^{10} - 1 = 1023 A = 4 \times 1023 A = 4092 F r o m (1), = 30 + 4092 = 4122

Regards!