Plwase solve i
Given, xy=yx ... (1)
and x2=y ... (2)
On putting the value of y in (1), we get
xy=(x2)x
⇒xy= x2x
⇒ y = 2x [On comparing the powers of like term]
⇒ x2 = 2x [using (2)]
⇒ x2 - 2x = 0
⇒ x(x - 2) = 0
⇒ x = 0 , 2
On putting the respective values of x in (2), we get
For x = 0, y = 02 = 0
and for x = 2, y = 22 = 4
Now, the values of x, y = 0, 0 can be discarded.
So, x + 2y = 2 + 2(4) = 2 + 8 = 10