Plz ans soon

Dear student,

Number of atoms in 1 mole of compound = 6.022 x 10²³

Number of atoms in 0.4 mol = 0.4 x 6.022 x 10²³

= 2.408 x 10²³

For a hexagonal closed packed structure,

Number of octahedral voids = number of atoms in the compound

Therefore, the number of octahedral voids = 2.408 x 10²³

And

Number of tetrahedral voids = 2 x octahedral voids

= 2 x 2.408 x 10²³

= 4.8176 x 10²³

The total number of voids = (4.8176 + 2.408 ) x 10²³

= 7.225 x 10^{23

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