Dear Student,The solution to your 3rd question is given below:Given,mb=2 4kg, r=1 2mA light rod is used So we can ignore the mass of the rod Moment of inertia of the ball i,I=mbr2=2 4×1 2×1 2=3 456≈3 5 kg m2For the remaining queries, please post them in separate threads soas to have rapid assistance from our experts Regards

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D e a r S t u d e n t, T h e s o l u t i o n t o y o u r 3^{r d} q u e s t i o n i s g i v e n b e l o w : G i v e n, m_{b} = 2.4 k g, r = 1.2 m A l i g h t r o d i s u s e d . S o w e c a n i g n o r e t h e m a s s o f t h e r o d . M o m e n t o f i n e r t i a o f t h e b a l l i, I = m_{b} r^{2} = 2.4 \times 1.2 \times 1.2 = 3.456 \approx 3.5 k g m^{2} F o r t h e r e m a i n i n g q u e r i e s, p l e a s e p o s t t h e m i n s e p a r a t e t h r e a d s s o a s t o h a v e r a p i d a s s i s t a n c e f r o m o u r e x p e r t s . R e g a r d s .

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