Plz answer

8. An open-ended wide tube is immersed vertically in mercury in such a way that a length 0.05 m extends above the mercury level. The open end of the tube is then closed and the tube is raised further by 0.43 m. If the length of the air column above the mercury level in the tube x 9in cm) find x/2
 

DEar Student
let the first condition that glass tube immeresed in the mercuryintial pressure of the enclosed air,P1=Atmospheric pressure =76 cm (Hg)cross sectional area=AVolume of the enclosed air V1=L1×A=5AIn the second case closed glass tube raised by the 43 cmlet us consider x=length of air collomn above the mercurytotal length=5+43=48 cmlength of mercury in the glass tube=48-xpressure of the enclosed air P2=Atm pressure-(52-x)=76-(48-x)=28+xVolume of the enclosed air V2=xAlet P1V1=P2V276×5A=(28+x)×(xA)380=28x+x2x2+28x-380=0(x+38)(x-10)=0x=-38x=10Negative value will be neglectedso x=10 cm
Regards

  • 5
What are you looking for?