Dear student Since FBCG is a straight lineSo, ∠ABF+∠ABC=180°⇒y+45°=180°⇒y=135°Also,∠ACG+∠ACB=180°⇒x+65°=180°⇒x=115°By angle sum property in △ABC, we have∠BAC+∠ABC+∠ACB=180°⇒z+45°+65°=180°⇒z=70° Regards

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Dear student

Since FBCG is a straight line So, ∠ ABF + ∠ ABC = 180 ° \Rightarrow y + 45 ° = 180 ° \Rightarrow y = 135 ° Also, ∠ ACG + ∠ ACB = 180 ° \Rightarrow x + 65 ° = 180 ° \Rightarrow x = 115 ° By angle sum property in △ ABC, we have ∠ BAC + ∠ ABC + ∠ ACB = 180 ° \Rightarrow z + 45 ° + 65 ° = 180 ° \Rightarrow z = 70 °

Regards

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