Plz answer my question

Solution,
Given,
wavelength of light, $\lambda =5000 \stackrel{o}{A}=5000\times {10}^{-10}m$
Energy of a photon is given by the relation:
$$\begin{gathered} E=h\nu =\frac{hc}{\lambda } \\ where, \\ h is the Planck\text{'}s cons\tan t and its value is 6.63\times {10}^{-34}Js \\ c is the speed of light, c=3\times {10}^{8}m/s \\ So, \\ Energy of t aphoton of wavelength \lambda =5000\times {10}^{-10}m is \\ E=\frac{6.63\times {10}^{-34}Js\times 3\times {10}^{8}m/s}{5000\times {10}^{-10}m}=3.98\times {10}^{-19}J \\ 1eV=1.6\times {10}^{-19}J \\ Thus, \\ 3.98\times {10}^{-19}J=\frac{3.98\times {10}^{-19}}{1.6\times {10}^{-19}}eV=2.49 eV \end{gathered}$$