Dear Student, as the interest is compounded annuallyA=P1+r100There P=15000,r=10 and T=2 years and 3 months3 months=312years=14yearshence Total Time T=2+14Amount at the end of 2 yearsA=15000×1+101002=15000×1+1102=15000×11102=15000×121100=150×121Amount at the end of 3 more months i e 14 years=150×121×111014=150×121×1 02411=18587 663 Hence she paid 18587 663 at the end of 2 years 3 months Regards,

plz answer Q5

plz answer Q5 5. Rani borrowed 15000 for 2 years 3 months at the rate 10% p.a. annually. How much money will she pay at the end of 2 years 3 rnontl-s? NOT 6. lent 20.10 to his friend at the rate of 8% p.a. interest m:xh money will he get back from his friend at the end of 2 years 9 % the the compound interest and simple interet at the rate annum, 8. Anisha a sum at compounded annually for 3 years. sarne amount iot same turne at same rate but at Simple interest. After üwestment. wto mu get more and by what amount? 9. what prmpal t±u• amount will in 2 years at the rate amually ? 10. Find tlr principal when CT for 2 years at the rate oi p.a„ interest (in yean) ! Example Solution

Dear Student,

a s t h e i n t e r e s t i s c o m p o u n d e d a n n u a l l y A = P {[1 + \frac{r}{100}]}^{T} h e r e P = 15000, r = 10 a n d T = 2 y e a r s a n d 3 m o n t h s 3 m o n t h s = \frac{3}{12} y e a r s = \frac{1}{4} y e a r s h e n c e T o t a l T i m e T = 2 + \frac{1}{4} A m o u n t a t t h e e n d o f 2 y e a r s A = 15000 \times {[1 + \frac{10}{100}]}^{2} = 15000 \times {[1 + \frac{1}{10}]}^{2} = 15000 \times {[\frac{11}{10}]}^{2} = 15000 \times \frac{121}{100} = 150 \times 121 A m o u n t a t t h e e n d o f 3 m o r e m o n t h s i . e \frac{1}{4} y e a r s = 150 \times 121 \times {(\frac{11}{10})}^{\frac{1}{4}} = 150 \times 121 \times 1.02411 = 18587.663

Hence she paid 18587.663 at the end of 2 years 3 months

Regards,

View Full Answer