Plz answer this
Dear Student,
In this figure
AB | | CD | | EF
And
Given AB= 7.5 cm, DC= y cm, EF= 4.5 cm, BC= x cm and CE= 3 cm
Now in BFE , we know CD | | EF , So from basic proportionality theorem , we get
So,
BD = x and DF = 3
Now in FBA , we know CD | | AB , So from basic proportionality theorem , we get
And
Now in BFE , we know CD | | EF , So from basic proportionality theorem , we get
Now we substitute value from equation 2 , in equation 1 , we get
From, Splitting the middle term method we get
x2 - 5x + 3x - 15 = 0
x ( x - 5 ) + 3 ( x - 5 ) = 0
( x - 5 ) ( x + 3 ) = 0
So,
x = 5 And - 3
But side of triangle can't be negative , So
x = 5 , Substitute that value in equation 2 , we het
y =
So,
x = 5 cm
And
y = 2 13 cm [Option 4]
16
Regards
In this figure
AB | | CD | | EF
And
Given AB= 7.5 cm, DC= y cm, EF= 4.5 cm, BC= x cm and CE= 3 cm
Now in BFE , we know CD | | EF , So from basic proportionality theorem , we get
So,
BD = x and DF = 3
Now in FBA , we know CD | | AB , So from basic proportionality theorem , we get
And
Now in BFE , we know CD | | EF , So from basic proportionality theorem , we get
Now we substitute value from equation 2 , in equation 1 , we get
From, Splitting the middle term method we get
x2 - 5x + 3x - 15 = 0
x ( x - 5 ) + 3 ( x - 5 ) = 0
( x - 5 ) ( x + 3 ) = 0
So,
x = 5 And - 3
But side of triangle can't be negative , So
x = 5 , Substitute that value in equation 2 , we het
y =
So,
x = 5 cm
And
y = 2 13 cm [Option 4]
16
Regards