Plz fast If the vertex and focus of a parabola are (3,3) and (-3,3) respectively,then its equation is:(a) - Maths - Conic Sections

Question

Plz fast

I f   t h e   v e r t e x   a n d   f o c u s
  o f   a   p a r a b o l a   a r e   ( 3
, 3 )   a n d   ( - 3 , 3 )   r e s p e c t i v e l
y , t h e n   i t s   e q u a t i o n   i s : ( a )
  x 2 - 6 x + 24 y - 63 = 0 ( b )   x 2 - 6 x + 24 y + 81
= 0 ( c )   y 2 - 6 y + 24 x - 63 = 0 ( d )   y 2 - 6 y -
24 x + 81 = 0

Amit Shukla · Accepted Answer

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Plz fast I f t h e v e r t e x a n d f o c u s o f a p a r a b o l a a r e ( 3 , 3 ) a n d ( - 3 , 3 ) r e s p e c t i v e l y , t h e n i t s e q u a t i o n i s : ( a ) x 2 - 6 x + 24 y - 63 = 0 ( b ) x 2 - 6 x + 24 y + 81 = 0 ( c ) y 2 - 6 y + 24 x - 63 = 0 ( d ) y 2 - 6 y - 24 x + 81 = 0

Plz fast

$I f t h e v e r t e x a n d f o c u s o f a p a r a b o l a a r e (3, 3) a n d (- 3, 3) r e s p e c t i v e l y, t h e n i t s e q u a t i o n i s : (a) x^{2} - 6 x + 24 y - 63 = 0 (b) x^{2} - 6 x + 24 y + 81 = 0 (c) y^{2} - 6 y + 24 x - 63 = 0 (d) y^{2} - 6 y - 24 x + 81 = 0$