Dear Student, 4 (i) 9sec2A - 9tanâ€‹2A = 9(sec2A - tan2â€‹A) = 9 x 1 = 9 [Since 1 + tan2A = sec2â€‹A, or, sec2A - tan2A = 1] â€‹For the remaining queries, we request you to post them in separate threads to have rapid assistance from our experts

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Dear Student,

4. (i) 9sec²A - 9tan²A = 9(sec²A - tan²A) = 9 x 1 = 9
[Since 1 + tan²A = sec²A, or, sec²A - tan²A = 1]

For the remaining queries, we request you to post them in separate threads to have rapid assistance from our experts.

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