# Plz give solution of sum number 52

$lettensionbeTinstringCandT\text{'}instringB\hspace{0.17em}\phantom{\rule{0ex}{0ex}}balancetheforces\phantom{\rule{0ex}{0ex}}T\mathrm{sin}45=T\text{'}\phantom{\rule{0ex}{0ex}}T\mathrm{sin}45=100g\phantom{\rule{0ex}{0ex}}T=100\sqrt{2}g\phantom{\rule{0ex}{0ex}}T\text{'}=100\sqrt{2}g\left(\frac{1}{\sqrt{2}}\right)=100gN\phantom{\rule{0ex}{0ex}}\phantom{\rule{0ex}{0ex}}Regards$

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