Plz help question no... 16 very very very urgent 
Plz help question no... 16 very very very urgent  (iii ) wnat mass 0T tne box, if the wood used weighs 0.9 g/crn3? rectangular plot of field measures 12 m by 15 m. A pit 8 m by 6m by 50 cm is dug U removed is spread evenly over the remaining portion of the field. Find the increase in the level the remaining portion of the field.

Dear Student, 
 

Given, Dimension of the field = 15 m × 12 m

Dimension of the pit = 8 m × 6m × 0.5 m              [1m=100 cm ]

Volume of earth removed from the pit = 8m × 6m × 0.5 m =24 m3

Area of the remaining field

= Area of the field – Area of the pit

= 15 m × 12 m – 8 m × 6 m

= 132 m2

Since, the earth removed is evenly spread over the remaining area of the field.

∴ Increase in level of remaining field × Area of remaining field  = Volume of earth removed from the pit

⇒ Increase in level of remaining field =

⇒ Increase in level of remaining field =
 

Thus, the increase in level of remaining field is 0.18m (approx) .


Regards

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