Plz help was asked in exam Q Prove :- - Maths -

Question

Plz help was asked in exam

Q Prove :-
tan 2 θ sec   θ   + 1 = 1   + cos  
θ 1   - cos   θ

Lovina Kansal · Accepted Answer

LHS=tan2θsecθ+1=sec2θ-1secθ+1   ∵tan2x+1=sec2x=secθ+1secθ-1secθ+1    ∵a2-b2=(a-b)(a+b)=secθ-1RHS=1+cosθ1-cosθ=1+cosθ1-cosθ×1+cosθ1+cosθ=1+cosθ21-cos2θ     =1+cos2θ+2sinθ cosθsin2θ     ∵a+b2=a2+b2+2ab=1+1-sin2θ+2sinθcosθsin2θ    ∵sin2x+cos2x=1=2+2sinθcosθ-sin2θsin2θPlease recheck your question
 LHS and RHS can never be equal

Plz help was asked in exam Q. Prove :- tan 2 θ sec θ + 1 = 1 + cos θ 1 - cos θ

Plz help was asked in exam

Q. Prove :-
$\frac{\tan^{2} θ}{\sec θ + 1} = \frac{1 + \cos θ}{1 - \cos θ}$