Plz solve it
Dear student,
We know , pH = -log[H+]
Given [H+] = 2.512 x 10-6 M
Substituting the value in the formula we get,
pH = -log[H+] = -log[ 2.512 x 10-6 ] = 6-log[2.512] = 6-0.40 = 5.60 .
Thus the pH of the solution is 5.60 .
Hope this information will clear your doubts about topic.
If you have any more doubts just ask here on the forum and our experts will try to help you out as soon as possible.
Regards
We know , pH = -log[H+]
Given [H+] = 2.512 x 10-6 M
Substituting the value in the formula we get,
pH = -log[H+] = -log[ 2.512 x 10-6 ] = 6-log[2.512] = 6-0.40 = 5.60 .
Thus the pH of the solution is 5.60 .
Hope this information will clear your doubts about topic.
If you have any more doubts just ask here on the forum and our experts will try to help you out as soon as possible.
Regards