Plz solve question 5first part 5. (i) (27)3 + (–17)3 + (–10)3 Share with your friends Share 0 Gursheen Kaur answered this Dear Student,Solution-273+-173+-103As we know that, x3+y3+z3-3xyz=(x+y+z) (x2+y2+z2-xy-yz-zx)So, x3+y3+z3=3xyz+(x+y+z) (x2+y2+z2-xy-yz-zx)Put x = 27, y = -17 and z = -10therefore, 273+-173+-103=3(27)(-17)(-10)+(27-17-10) 272+(-17)2+(-10)2-(27X-17)-(-17X-10)-(-10X27)=3(27)(-17)(-10)+(0) 272+(-17)2+(-10)2-(27X-17)-(-17X-10)-(-10X27)=3(27)(-17)(-10)+0=13770Regards! 0 View Full Answer Divesh Mehta answered this Please find this answer 1
