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D e a r S t u d e n t, 3 Ω a n d 6 Ω a r e i n p a r a l l e l . T h e r e f o r e, R_{p} = \frac{3 \times 6}{3 + 6} = \frac{18}{9} = 2 Ω N o w, R_{p} a n d 8 Ω a r e i n s e r i e s . R_{s} = R_{p} + 8 = 2 + 8 = 10 Ω N o w, 10 Ω a n d R_{s} a r e i n p a r a l l e l . R_{A B} = \frac{10 \times 30}{10 + 30} = \frac{300}{40} = 7.5 Ω, O p t i o n 3 R e g a r d s

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