Plz solve this numerical
Dear Student
Solutions for question number 8th & 9th is provided below
answer 8th
given :T / l² = 360 dyne/cm²
Solutions for question number 8th & 9th is provided below
answer 8th
given :T / l² = 360 dyne/cm²
n = 300 Hz
n = 1/2l [√ T / M]
n ² =[ 1/4l² ] [T/ M]
M=1/4n² [T/l²)
M=[1/4x(300)²] x [360/1)
M=90/90000
M=10⁻³ g/cm
M=10⁻⁴kg/m
Answer 9th
Given :
When wire is stretched by a weight hanging vertically,
n1 = 250 Hz
, Frequency of wire when the weight is immersed in water producing 10 beats per second = n2
∴ n2 = n1 – 10 = 250 – 10 = 240 Hz
ρ w = 1 g/cc
n1/n2=√(ρ/ (ρ-1)
250/240=√[ρ/ (ρ-1)]
25/24= √ρ/ (ρ-1)
Squaring on both sides=
625/576= ρ/ (ρ-1)
625(ρ-1)=576 ρ
625 ρ-576 ρ=625
49 ρ=625
Ρ=625/49
=12.76g/cm3
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