Plz solve this
Q.26. The mass string system shown in the figure is in equilibrium. If the coefficient of friction between A and the table is 0.3, the frictional force on A is :-


(1) 9.8 N
(2) 2.04 N
(3) 1.96 N
(4) 0.59 N

Dear Student,let the tenson in the string attached to A is Tstring attached to the celing has tension T'balance the force about the point .T'cos45=TT'cos45=0.2gT=0.2g=0.2*9.8=1.96 N this force is equal to frictional force .f=1.96 Noption 3Regards

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