Plz solve this question no.3?? Fst

Dear Student,
sec254° - cot236°cosec257° - tan233° + 2sin238° sec252° - sin245°cot36 = tan(90-36) = tan54we know that sec254 - tan254 = 1tan33 = cot(90-33) = cot 57we know that cosec257 - cot257 = 1sec52 = cosec(90-52) = cosec38then sin238×cosec238 = 1sin245 = 1/2substituting these all in given equation11 + 2×1 - 12 = 1 + 2 - 12 3 -12 = 6-12 = 52
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