Plz solve this question..
Join OP and OQ.
In OPS and OQS:
OP=OQ……Radius of circle
OPS=OQS=900 (Tangent is to the radius through the point of contact)
Therefore, by Right angle-Hypotenuse-Side criterion of congruence, we have
OPS OQS (RHS)
The corresponding parts of the congruent triangles are congruent.
POS = QOS……cpct,
OSP = OSQ ……..cpct
POQ+PSQ=1800 as the total sum of interior angles in a quadrilateral=3600
So OSP = OSQ = 45oAs PSQ=900
STC=900 sum of two co interior angles is 180 o.
SOT is an isosceles triangle having two sides:
Similarly, QOT = 45o
SOT = 90o