Plz solve this

Plz solve this In the given diagram, m2 can slide on the smooth horizontal surface. The pulleys are small. At an instant the block mt comes down with velocity of 3 m/s. At this instant 0 600. Find the magnitude of velocity of ma at this instant in mls.

Dear Student,
At the instant when $\theta ={60}^o$,​​​ the magnitude of velocity of m₂ is L m/s, i.e., the distance that can be travelled in 1 s is L m.
Then the rate at which the string in the inclined section will move will be L/cos60 m/s i.e., the distance that can be travelled in 1 s is 2L m.
Thus, the net rate at which mass m1 travels at that instant will be L + 2L = 3L in one sec.
Therefore, 3L m/s = 3m/s This implies that L = 1 m. 
Thus, the speed with which m₂ slides will be 1m/s.

Regards,