Plz solve this

Dear student 
Let the distance between A and B is x km
From A to B train travels wih speed 60 km/hr
Time taken by train on going from A to B = x/60 hr.
From B to A train travels with speed 80 km/hr 
Time taken by train coming from B to A = x/80 hr 
i) Average speed = Total distance travelled / total time taken 
                                                                                                                                                                                                                   
 $$\begin{gathered} = \frac{x+ x}{{\displaystyle \frac{x}{60}}+{\displaystyle \frac{x}{80}}} \\ = \frac{2x}{{\displaystyle \frac{4x+3x}{240}}} \\ = \frac{480}{7} km/hr \\ = 68.57 km/hr \end{gathered}$$
ii)  Average velocity = Total displacement / Total time 
The particle is at initial position here , So net displacement = 0 km 
So Average velocity = 0 / Time taken 
Average velocity = 0 km/h 

Regards 


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