plz someone help me in solving this question i need the answer now. Share with your friends Share 1 Hempushp Katara answered this Dear Student Applying magnification formula as height of object and height of image is givenho = 1.5cm= height of objecthi =0.7cm = height of imagev =image distanceu = object distancef = focal length m = hi/ho =v/u0.7/1.5 = v/uv/u = 7/15dividing distance of 8cm in 7:15 ratiov = (7/22)×8 cm = 2.55cmu =- (15/22)×8 cm =- 5.45cm {left to lens} (i) The lens would be placed at 5.45 cm from AB object.(ii) As the image is formed erect and back side to lens then lens must be of diverging type i.e. Concave Lens(iii) Applying lens formula1/V -1/U = 1/f1/ (7/22)×8 - 1/(-15/22)×8 = 1/f22/56 +22/120 = 1/f121/210 =1/ff = 210/121 = 1.74cm Regards 0 View Full Answer
