Plzz give solution of Q 9

Dear student,

Let, the two charges be Q and q separated by a distance r

q1 =  
q2 = 
r = 8 cm
E = electric field

Since q1 & q2 have opposite sign so the point at which the electric field is zero will lie beyond the position vector joining the two charges

 

Let, x be the position of the point P where resultant electric field is zero.

E1 = electric field of q1 at x

E2 = electric field of q2 at x
Given,






Hence at 32 cm from charge  the electric field is zero.


Hence at 32 - 8 =24  cm from charge  the electric field is zero.

Option A is correct
Regards

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