Plzz give solution of Q 9
Dear student,
Hence at 32 - 8 =24 cm from charge the electric field is zero.
Option A is correct
Regards
Let, the two charges be Q and q separated by a distance r
q1 =
q2 =
r = 8 cm
E = electric field
Since q1 & q2 have opposite sign so the point at which the electric field is zero will lie beyond the position vector joining the two charges
Let, x be the position of the point P where resultant electric field is zero.
E1 = electric field of q1 at x
E2 = electric field of q2 at x
Given,
Hence at 32 cm from charge the electric field is zero.
Hence at 32 - 8 =24 cm from charge the electric field is zero.
Option A is correct
Regards