Plzz help in 20th one

Plzz help in 20th one bring down the prices back to so as must 20. The sides ofa rectangle are 40 cm by 30 cm. If each 'Side is increased by 10%, find the percentage increase in the area. out of O,

Dear Student,
The new sides will be 44 cm and 33 cm

40 + 40 \times \frac{10}{100} = 40 + 4 = 44 c m 30 + 30 \times \frac{10}{100} = 30 + 3 = 33 c m

Area= length

\times

breadth
=

44 \times 33 = 1452 c m^{2}

The earlier area was=

40 \times 30

= 1200

c m^{2}

Increase in area= 1452-1200= 252

c m^{2}

I n c r e a s e i n p e r c e n t a g e = \frac{C h a g e i n a r e a}{I n i t i a l a r e a} \times 100 = \frac{252}{1200} \times 100 = 21 %

Regards