Plzz help in this

Dear Student,

Please find below the solution to the asked query:

Let , Original price = x

So, from given condition we get new price = x + 20 % of x  = x + $\frac{20 x}{100} = x +\hspace{0.17em}\frac{{\displaystyle x}}{{\displaystyle 5}} = \frac{\mathbf{6}\mathbf{ }\mathbf{x}}{\mathbf{5}}$

Let , Price bring down by y% so we get original price back , So 

$$\begin{gathered} \frac{6 x}{5} - y\% \mathrm{of} \frac{6 x}{5} = x \\ \Rightarrow \frac{6 x}{5} -\frac{{\displaystyle \frac{6 x}{5}}\times y }{100}= x \\ \Rightarrow \frac{6 x}{5}\left(1 -\frac{{\displaystyle y }}{100}\right)= x \\ \Rightarrow \frac{{\displaystyle 100 - y }}{100}= x \times \frac{5}{6 x} \\ \Rightarrow \frac{{\displaystyle 100 - y }}{100}= \frac{5}{6} \\ \Rightarrow 600 - 6 y = 500 \\ \Rightarrow 6 y =100 \\ \Rightarrow y =\frac{100}{6} \\ \mathbf{\Rightarrow }\mathbf{ }\mathit{y}\mathbf{ }\mathbf{=}\mathbf{16}\mathbf{.}\mathbf{67}\mathbf{ }\mathbf{\%}\mathbf{ }\mathbf{ }\mathbf{ }\mathbf{ }\mathbf{ }\mathbf{ }\mathbf{ }\mathbf{ }\mathbf{ }\mathbf{ }\mathbf{ }\mathbf{ }\mathbf{ }\mathbf{ }\mathbf{ }\mathbf{ }\mathbf{ }\mathbf{ }\mathbf{ }\mathbf{ }\mathbf{ }\mathbf{ }\left(\mathbf{Ans}\right) \end{gathered}$$
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