plzz solve it
Dear Student,
Wavelength (λ) = 616 nm = 616*10-9
(a) The frequency of emission is c/λ= (3.0*108)/(616*10−9)=4.87*1014 Hz; c is the speed of light
(b) The distance traveled in 30 s is
distance = time* velocity = time * wavelength*frequency
d=t*λ*ν
=30*616*10−9*4.87*1014=9.0*109m.
(c) The energy of quanta is E=hν=6.626*10−34*4.87*1014=3.227*10−19J.; h is the Planck's constant
(d) The number of quanta in 2J of energy = Total Energy/ Energy of 1 quanta =2/( 3.227*10−19) = 6.2*1018 quanta.
Regards
Wavelength (λ) = 616 nm = 616*10-9
(a) The frequency of emission is c/λ= (3.0*108)/(616*10−9)=4.87*1014 Hz; c is the speed of light
(b) The distance traveled in 30 s is
distance = time* velocity = time * wavelength*frequency
d=t*λ*ν
=30*616*10−9*4.87*1014=9.0*109m.
(c) The energy of quanta is E=hν=6.626*10−34*4.87*1014=3.227*10−19J.; h is the Planck's constant
(d) The number of quanta in 2J of energy = Total Energy/ Energy of 1 quanta =2/( 3.227*10−19) = 6.2*1018 quanta.
Regards