Plzz solve the third question no link plzz
Q.3. Given A = 60 ° and B = 30 °
Prove that tan   ( A + B ) = tan   A + tan   B 1 - tan   A tan   B

Dear Student,

Given: A = 60° and B = 30°To prove: tanA + B = tanA + tanB1 - tanAtanBProof: LHS = tanA + B = tan60° + 30° = tan90° = RHS = tanA + tanB1 - tanAtanB = tan60° + tan30°1 - tan60°tan30° = 3 + 131 - 313 = 3 + 130 =  LHS = RHS.Hence, proved.

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